Regular Expression
Basic Regex
Character types
\w
matches with any alphanumeric character, including underline-
.
matches to all characters, including symbols (Wildcard) -
\d
matches to all single digits [0-9] -
\s
matches to all single space, tab and new line -
\.
matches to the dot(period) character [a-z]
小寫英文字母 a-z[A-Z]
大寫英文字母 A-Z[^a-z]
非小寫英文字母 a-z[0-9]
數字 0-9[^0-9]
反向列舉,任意非數字|
左邊字元或右邊字元p?each
字元 each 前方包含 0 個或 1 個 p 字元,each 或 peach
import re
re.findall("\w", "h32rb17")
import re
re.findall("\d", "h32rb17")
邊界符號
^
行首$
行尾\b
必須是單詞 (文字、數字、底線) 的開頭或結尾\B
不能是單詞 (文字、數字、底線) 的開頭或結尾
Quantify occurrences
次數符號,限定符號
+
: 重複 1 次以上,同{1,}
*
: 重複 0 次以上,同{0,}
?
: 重複 0 或 1 次,範例p?each
字元 each 前方包含 0 個或 1 個 p 字元,例如 each 或 peach{n}
: 重複 n 次{n,}
: 重複 n 次以上{0,n}
: 重複 0 - n 次{n,m}
: 重複 n - m 次\d{2}
2 位數的數字\d{1,3}
數字 1 - 3 位數\d+
不限位數的任何數字
Functions
.findall()
.findall(<regex>, <string>)
- 搜尋符合的所有字元
- 輸出格式 List
import re
re.findall("\d+", "h32rb17")
import re
re.findall("\d*", "h32rb17")
import re
re.findall("\d{2}", "h32rb17 k825t0m c2994eh")
import re
re.findall("\d{1,3}", "h32rb17 k825t0m c2994eh")
import re
pattern = "\w+:\s\d+"
employee_logins_string = "1001 bmoreno: 12 Marketing 1002 tshah: 7 Human Resources 1003 sgilmore: 5 Finance"
print(re.findall(pattern, employee_logins_string))
['bmoreno: 12', 'tshah: 7', 'sgilmore: 5']
.search()
.search(<regex>, <string>, re.IGNORECASE)
- r"regex" :
r
表示 raw string,Python 直譯器不會解譯該字串,而是直接傳給函式 - 只搜尋符合的第一個字元
- 輸出格式 Match Class
import re
log = "July 31 07:51:48 mycomputer bad_process[12345]: ERROR Performing package upgrade"
regex = r"\[(\d+)\]"
result = re.search(regex, log)
print(result) # Output: <_sre.SRE_Match object; span=(39, 46), match='[12345]'>
print(result[1]) # Output: 12345
import re
print(re.search(r"[Pp]ython", "Python"))
# Output: <_sre.SRE_Match object; span=(0, 6), match='Python'>
import re
print(re.search(r"Py.*n", "Pygmalion"))
print(re.search(r"Py.*n", "Python Programming"))
print(re.search(r"Py[a-z]*n", "Python Programming"))
print(re.search(r"Py[a-z]*n", "Pyn"))
# Output:
# <_sre.SRE_Match object; span=(0, 9), match='Pygmalion'>
# <_sre.SRE_Match object; span=(0, 17), match='Python Programmin'>
# <_sre.SRE_Match object; span=(0, 6), match='Python'>
# <_sre.SRE_Match object; span=(0, 3), match='Pyn'>
import re
print(re.search(r"o+l+", "goldfish"))
print(re.search(r"o+l+", "woolly"))
print(re.search(r"o+l+", "boil"))
# Output:
# <_sre.SRE_Match object; span=(1, 3), match='ol'>
# <_sre.SRE_Match object; span=(1, 5), match='ooll'>
# None
.split()
- 用途:用 Regex 分割長字串
.split(<regex>, <string>)
: 輸出 List 資料格式r"[.?!]"
多個不同單一字元做區隔符號可用中括號,且特殊符號不需要使用跳脫字元
import re
re.split(r"[.?!]", "One sentence. Another one? And the last one!")
# Output: ['One sentence', ' Another one', ' And the last one', '']
r"the|a"
: 多個不同單字做區隔符號可用導管
re.split(r"the|a", "One sentence. Another one? And the last one!")
# Output: ['One sentence. Ano', 'r one? And ', ' l', 'st one!']
r"([.?!])"
區隔符號用中括號,不需要使用跳脫符號,外圍加上括號時,輸出會包含區隔符號
import re
re.split(r"([.?!])", "One sentence. Another one? And the last one!")
# Output: ['One sentence', '.', ' Another one', '?', ' And the last one', '!', '']
.sub()
- 用途:搜尋並取代字串
.sub(<regex>, <new-string>, <strings>)
: 符合 <regex> 的字串會被 <new-string>取代
import re
re.sub(r"[\w.%+-]+@[\w.-]+", "[REDACTED]", "Received an email for go_nuts95@my.example.com")
# Output: Received an email for [REDACTED]
re.sub(r"([A-Z])\.\s+(\w+)", r"Ms. \2", "A. Weber and B. Bellmas have joined the team.")
# Output: Ms. Weber and Ms. Bellmas have joined the team
- 搜尋與取代都能使用 Regex
- 搜尋 regex :
r"^([\w .-]*), ([\w .-]*)$"
,(群組1), (群組2) - 取代 regex:
r"\2 \1"
,\2 群組2,\1 群組1
import re
re.sub(r"^([\w .-]*), ([\w .-]*)$", r"\2 \1", "Lovelace, Ada")
# Output: Ada Lovelace
Advanced Regex
多個選項
Alteration: RegEx that matches any one of the alternatives separated by the pipe symbol
r"location.*(London|Berlin|Madrid)"
: location is London, location is Berlin, or location is Madrid.
字元範圍
r"[0-9$-,.]"
: This will match any of the digits zero through nine, or the dollar sign, hyphen, comma, or period
常用驗證
r"\d{3}-\d{3}-\d{4}"
This line of code matches U.S. phone numbers in the format 111-222-3333.r"^-?\d*(\.\d+)?$"
任何正數或負數,不論是否有小數位數r"^(.+)\/([^\/]+)\/"
任何檔案路徑
IP addr.
# Assign `log_file` to a string containing username, date, login time, and IP address for a series of login attempts
log_file = "eraab 2022-05-10 6:03:41 192.168.152.148 \niuduike 2022-05-09 6:46:40 192.168.22.115 \nsmartell 2022-05-09 19:30:32 192.168.190.178 \narutley 2022-05-12 17:00:59 1923.1689.3.24 \nrjensen 2022-05-11 0:59:26 192.168.213.128 \naestrada 2022-05-09 19:28:12 1924.1680.27.57 \nasundara 2022-05-11 18:38:07 192.168.96.200 \ndkot 2022-05-12 10:52:00 1921.168.1283.75 \nabernard 2022-05-12 23:38:46 19245.168.2345.49 \ncjackson 2022-05-12 19:36:42 192.168.247.153 \njclark 2022-05-10 10:48:02 192.168.174.117 \nalevitsk 2022-05-08 12:09:10 192.16874.1390.176 \njrafael 2022-05-10 22:40:01 192.168.148.115 \nyappiah 2022-05-12 10:37:22 192.168.103.10654 \ndaquino 2022-05-08 7:02:35 192.168.168.144"
# Assign `pattern` to a regular expression that matches with all valid IP addresses and only those
pattern = "\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}"
# Use `re.findall()` on `pattern` and `log_file` and assign `valid_ip_addresses` to the output
valid_ip_addresses = re.findall(pattern, log_file)
# Assign `flagged_addresses` to a list of IP addresses that have been previously flagged for unusual activity
flagged_addresses = ["192.168.190.178", "192.168.96.200", "192.168.174.117", "192.168.168.144"]
# Iterative statement begins here
# Loop through `valid_ip_addresses` with `address` as the loop variable
for address in valid_ip_addresses:
# Conditional begins here
# If `address` belongs to `flagged_addresses`, display "The IP address ______ has been flagged for further analysis."
if address in flagged_addresses:
print("The IP address", address, "has been flagged for further analysis.")
# Otherwise, display "The IP address ______ does not require further analysis."
else:
print("The IP address", address, "does not require further analysis.")
檢查字串函式
回傳結果 True 或 False
import re
def check_aei (text):
result = re.search(r".*a.+e.+i.*", text)
return result != None
print(check_aei("academia")) # True
print(check_aei("aerial")) # False
print(check_aei("paramedic")) # True
函式: 檢查字串是否有包含任何標點符號
import re
def check_punctuation (text):
result = re.search(r"[^a-zA-Z ]", text)
return result != None
print(check_punctuation("This is a sentence that ends with a period.")) # True
print(check_punctuation("This is a sentence fragment without a period")) # False
print(check_punctuation("Aren't regular expressions awesome?")) # True
函式:check web address
import re
def check_web_address(text):
pattern = r"[\w-]*\.[a-zA-Z]*$"
result = re.search(pattern, text)
return result != None
print(check_web_address("gmail.com")) # True
print(check_web_address("www@google")) # False
print(check_web_address("www.Coursera.org")) # True
print(check_web_address("web-address.com/homepage")) # False
print(check_web_address("My_Favorite-Blog.US")) # True
函式:check time
import re
def check_time(text):
pattern = r"[1-9|10|11|12]:[0-5][0-9] *[AaPp][mM]$"
result = re.search(pattern, text)
return result != None
print(check_time("12:45pm")) # True
print(check_time("9:59 AM")) # True
print(check_time("6:60am")) # False
print(check_time("five o'clock")) # False
print(check_time("6:02 am")) # True
print(check_time("6:02km")) # False
函式:括號內的字首需大寫字母或數字
import re
def contains_acronym(text):
pattern = r"\([0-9A-Z][a-zA-z]*\)"
result = re.search(pattern, text)
return result != None
print(contains_acronym("Instant messaging (IM) is a set of communication technologies used for text-based communication")) # True
print(contains_acronym("American Standard Code for Information Interchange (ASCII) is a character encoding standard for electronic communication")) # True
print(contains_acronym("Please do NOT enter without permission!")) # False
print(contains_acronym("PostScript is a fourth-generation programming language (4GL)")) # True
print(contains_acronym("Have fun using a self-contained underwater breathing apparatus (Scuba)!")) # True
函式:Log 提取 PID 與 Message
import re
def extract_pid(log_line):
regex = r"\[(\d+)\]: ([A-Z]*) "
result = re.search(regex, log_line)
if result is None:
return None
return "{} ({})".format(result[1], result[2])
print(extract_pid("July 31 07:51:48 mycomputer bad_process[12345]: ERROR Performing package upgrade")) # 12345 (ERROR)
print(extract_pid("99 elephants in a [cage]")) # None
print(extract_pid("A string that also has numbers [34567] but no uppercase message")) # None
print(extract_pid("July 31 08:08:08 mycomputer new_process[67890]: RUNNING Performing backup")) # 67890 (RUNNING)
函式:轉換電話號碼
import re
def transform_record(record):
new_record = re.sub(r"(.*,)(\d{3}-[\d-]+)(,.*)", r"\1+1-\2\3", record)
return new_record
print(transform_record("Sabrina Green,802-867-5309,System Administrator"))
# Sabrina Green,+1-802-867-5309,System Administrator
print(transform_record("Eli Jones,684-3481127,IT specialist"))
# Eli Jones,+1-684-3481127,IT specialist
print(transform_record("Melody Daniels,846-687-7436,Programmer"))
# Melody Daniels,+1-846-687-7436,Programmer
print(transform_record("Charlie Rivera,698-746-3357,Web Developer"))
# Charlie Rivera,+1-698-746-3357,Web Developer
import re
def convert_phone_number(phone):
result = re.sub(r"([\w ]+)(\d{3})-(\d{3}-\d{4}.*)$", r"\1(\2) \3", phone)
return result
print(convert_phone_number("My number is 212-345-9999.")) # My number is (212) 345-9999.
print(convert_phone_number("Please call 888-555-1234")) # Please call (888) 555-1234
print(convert_phone_number("123-123-12345")) # 123-123-12345
print(convert_phone_number("Phone number of Buckingham Palace is +44 303 123 7300")) # Phone number of Buckingham Palace is +44 303 123 7300
函式:包含 a, e, i, o, u 任一字元 3 個以上的單字
import re
def multi_vowel_words(text):
pattern = r"\w+[aeiou]{3,}\w+"
result = re.findall(pattern, text)
return result
print(multi_vowel_words("Life is beautiful"))
# ['beautiful']
print(multi_vowel_words("Obviously, the queen is courageous and gracious."))
# ['Obviously', 'queen', 'courageous', 'gracious']
print(multi_vowel_words("The rambunctious children had to sit quietly and await their delicious dinner."))
# ['rambunctious', 'quietly', 'delicious']
print(multi_vowel_words("The order of a data queue is First In First Out (FIFO)"))
# ['queue']
print(multi_vowel_words("Hello world!"))
# []
\b 的用法
\b
必須是單詞 (文字、數字、底線) 的開頭或結尾
import re
print(re.findall(r"[a-zA-Z]{5}", "a scary ghost appeared"))
# Output: ['scary', 'ghost', 'appea']
import re
re.findall(r"\b[a-zA-Z]{5}\b", "A scary ghost appeared")
# Output: ['scary', 'ghost']
- 結尾如果不加
\b
無法正確搜尋所有的 eid
def find_eid(report):
pattern = r"[A-Z]-[\d]{7,8}\b" #enter the regex pattern here
result = re.findall(pattern, report) #enter the re method here
return result
print(find_eid("Employees B-1234567 and C-12345678 worked with products X-123456 and Z-123456789"))
# Should return ['B-1234567', 'C-12345678']
print(find_eid("Employees B-1234567 and C-12345678, not employees b-1234567 and c-12345678"))
#Should return ['B-1234567', 'C-12345678']
Capturing Groups
- 用途:提取字串中符合 Regex 規則的不同文字區段
- 特定字元區段的 Regex 可用括號定義成群組
- 多個括號時,依序為群組1,群組2
.groups()
method : 輸出 tuple 格式資料,例如 (group1, group2, group3)- result[0]: 完整字串 ,result[1]: 群組1, result[2]: 群組2
import re
result = re.search(r"^(\w*), (\w*)$", "Lovelace, Ada")
print(result)
print(result.groups())
print(result[0])
print(result[1])
print(result[2])
"{} {}".format(result[2], result[1])
# Output
# <_sre.SRE_Match object; span=(0, 13), match='Lovelace, Ada'>
# ('Lovelace', 'Ada')
# Lovelace, Ada
# Lovelace
# Ada
# Ada Lovelace