Regular Expression
Character types
\w
matches with any alphanumeric character-
.
matches to all characters, including symbols -
\d
matches to all single digits [0-9] -
\s
matches to all single spaces -
\.
matches to the period character [a-z]
小寫英文字母 a-z[A-Z]
大寫英文字母 A-Z- [^a-z] 非小寫英文字母 a-z
[0-9]
數字 0-9^
行首$
行尾|
左邊字元或右邊字元p?each
字元 each 前方包含 0 個或 1 個 p 字元,each 或 peach
import re
re.findall("\w", "h32rb17")
import re
re.findall("\d", "h32rb17")
Quantify occurrences
+
symbol represents one or more occurrences of a specific character.*
symbol represents zero, one, or more occurrences of a specific character.\d{2}
instructs Python to return all matches of exactly two single digits\d{1,3}
數字 1 - 3 位數
Functions
.findall(<regex>, <string>)
- 搜尋符合的所有字元
- 輸出格式 List
import re
re.findall("\d+", "h32rb17")
import re
re.findall("\d*", "h32rb17")
import re
re.findall("\d{2}", "h32rb17 k825t0m c2994eh")
import re
re.findall("\d{1,3}", "h32rb17 k825t0m c2994eh")
import re
pattern = "\w+:\s\d+"
employee_logins_string = "1001 bmoreno: 12 Marketing 1002 tshah: 7 Human Resources 1003 sgilmore: 5 Finance"
print(re.findall(pattern, employee_logins_string))
['bmoreno: 12', 'tshah: 7', 'sgilmore: 5']
.search(<regex>, <string>, re.IGNORECASE)
- r"regex" :
r
表示 raw string,Python 直譯器不會解譯該字串,而是直接傳給函式 - 只搜尋符合的第一個字元
- 輸出格式 Match Class
import re
log = "July 31 07:51:48 mycomputer bad_process[12345]: ERROR Performing package upgrade"
regex = r"\[(\d+)\]"
result = re.search(regex, log)
print(result) # Output: <_sre.SRE_Match object; span=(39, 46), match='[12345]'>
print(result[1]) # Output: 12345
import re
print(re.search(r"[Pp]ython", "Python"))
# Output: <_sre.SRE_Match object; span=(0, 6), match='Python'>
import re
print(re.search(r"Py.*n", "Pygmalion"))
print(re.search(r"Py.*n", "Python Programming"))
print(re.search(r"Py[a-z]*n", "Python Programming"))
print(re.search(r"Py[a-z]*n", "Pyn"))
# Output:
# <_sre.SRE_Match object; span=(0, 9), match='Pygmalion'>
# <_sre.SRE_Match object; span=(0, 17), match='Python Programmin'>
# <_sre.SRE_Match object; span=(0, 6), match='Python'>
# <_sre.SRE_Match object; span=(0, 3), match='Pyn'>
import re
print(re.search(r"o+l+", "goldfish"))
print(re.search(r"o+l+", "woolly"))
print(re.search(r"o+l+", "boil"))
# Output:
# <_sre.SRE_Match object; span=(1, 3), match='ol'>
# <_sre.SRE_Match object; span=(1, 5), match='ooll'>
# None
IP addr.
# Assign `log_file` to a string containing username, date, login time, and IP address for a series of login attempts
log_file = "eraab 2022-05-10 6:03:41 192.168.152.148 \niuduike 2022-05-09 6:46:40 192.168.22.115 \nsmartell 2022-05-09 19:30:32 192.168.190.178 \narutley 2022-05-12 17:00:59 1923.1689.3.24 \nrjensen 2022-05-11 0:59:26 192.168.213.128 \naestrada 2022-05-09 19:28:12 1924.1680.27.57 \nasundara 2022-05-11 18:38:07 192.168.96.200 \ndkot 2022-05-12 10:52:00 1921.168.1283.75 \nabernard 2022-05-12 23:38:46 19245.168.2345.49 \ncjackson 2022-05-12 19:36:42 192.168.247.153 \njclark 2022-05-10 10:48:02 192.168.174.117 \nalevitsk 2022-05-08 12:09:10 192.16874.1390.176 \njrafael 2022-05-10 22:40:01 192.168.148.115 \nyappiah 2022-05-12 10:37:22 192.168.103.10654 \ndaquino 2022-05-08 7:02:35 192.168.168.144"
# Assign `pattern` to a regular expression that matches with all valid IP addresses and only those
pattern = "\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}"
# Use `re.findall()` on `pattern` and `log_file` and assign `valid_ip_addresses` to the output
valid_ip_addresses = re.findall(pattern, log_file)
# Assign `flagged_addresses` to a list of IP addresses that have been previously flagged for unusual activity
flagged_addresses = ["192.168.190.178", "192.168.96.200", "192.168.174.117", "192.168.168.144"]
# Iterative statement begins here
# Loop through `valid_ip_addresses` with `address` as the loop variable
for address in valid_ip_addresses:
# Conditional begins here
# If `address` belongs to `flagged_addresses`, display "The IP address ______ has been flagged for further analysis."
if address in flagged_addresses:
print("The IP address", address, "has been flagged for further analysis.")
# Otherwise, display "The IP address ______ does not require further analysis."
else:
print("The IP address", address, "does not require further analysis.")
檢查字串函式
回傳結果 True 或 False
import re
def check_aei (text):
result = re.search(r".*a.+e.+i.*", text)
return result != None
print(check_aei("academia")) # True
print(check_aei("aerial")) # False
print(check_aei("paramedic")) # True
函式: 檢查字串是否有包含任何標點符號
import re
def check_punctuation (text):
result = re.search(r"[^a-zA-Z ]", text)
return result != None
print(check_punctuation("This is a sentence that ends with a period.")) # True
print(check_punctuation("This is a sentence fragment without a period")) # False
print(check_punctuation("Aren't regular expressions awesome?")) # True